Key Concept: Critical Thinking, Advanced Application
b) 60,000 liters
[Solution Description] To determine the volume of water collected, we use the formula $V = A \times R \times E$, where A is the area in square meters, R is the rainfall in liters per square meter, and E is the efficiency.
Firstly, calculate the total rainfall on the area:
$ V_{\text{total}} = A \times R = 100 \, \text{m}^2 \times 800 \, \text{mm} $
Convert rainfall from mm to liters $(1 \, \text{mm} = 1 \, \text{L/m}^2)$:
$ V_{\text{total}} = 100 \times 800 = 80,000 \, \text{liters} $
Now apply the efficiency:
$ V_{\text{collected}} = V_{\text{total}} \times E = 80,000 \times 0.75 = 60,000 \, \text{liters} $
Thus, the expected volume of water collected annually is 60,000 liters.
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Your Answer is correct.
b) 60,000 liters
[Solution Description] To determine the volume of water collected, we use the formula $V = A \times R \times E$, where A is the area in square meters, R is the rainfall in liters per square meter, and E is the efficiency.
Firstly, calculate the total rainfall on the area:
$V_{\text{total}} = A \times R = 100 \, \text{m}^2 \times 800 \, \text{mm}$
Convert rainfall from mm to liters $(1 \, \text{mm} = 1 \, \text{L/m}^2)$:
$V_{\text{total}} = 100 \times 800 = 80,000 \, \text{liters}$
Now apply the efficiency:
$V_{\text{collected}} = V_{\text{total}} \times E = 80,000 \times 0.75 = 60,000 \, \text{liters}$
Thus, the expected volume of water collected annually is 60,000 liters.